A ball falls from rest through a height of 92.5cm in 0.45s. find the acceleration due to gravity.
\( \frac{0.45^2×100}{92.5 ms^{-2}}\)
\( \frac{2×92.5}{0.45^2×100} ms^{-2}\)
\( \frac{0.45^2×100}{2×92.5 ms^{-2}}\)
\( \frac{0.95}{0.45^2×100 ms^{-2}}\)
