Given that \(log_{10}\;x=1.699 \;\;and\;\; log_{10}\;y=1.915,\) evaluate without using tables or calculators: \(log_{10}\;x+log_{10} \;\;\; y^⅓ \)
\(2.337\)
\(3.213\)
\(1.324\)
\(0.334\)
