Butane burns in excess air according to the following equation. \(2C_4 H_10 (g)+130_2 (g) \rightarrow 8CO_2 (g)+10H_2 O(l) ∆H=-5760 KJ mol^-1\) The amount of heat evolved when 2.4dm3 of butane is burnt at room temperature is;
\(5760 ×2.4\over2×24\)
\(5760 ×2.4\over22.4\)
\(5760 ×2.4\over2×22.4\)
\( 5760 ×2.4\over24\)